Lec 20: Alarms, sigaction()
, and Reentrant System Calls
Table of Contents
1 Alarm Signals and SIGALRM
In the last lesson, we explored signal handling and user generated
signals, particularly those from the terminal, the SIGKILL
, and
the user signals, or the SIGUSR1
and SIGUSR2
. In this lessons,
we'll explore O.S. generated signals. We'll start with SIGALRM
.
1.1 Setting an alarm
A SIGALRM
signal is delivered by the Operating System via a
request from the user occuring after some amount of time. To
request an alarm, use the alarm()
system call:
unsigned int alarm(unsigned int seconds);
After seconds
have passed since requesting the alarm()
, the
SIGALRM
signal is delivered. The default behavior of SIGALRM
is
to terminate, so we can catch and handle the signal, leading to a
nice hello world program:
#include <stdio.h> #include <stdlib.h> #include <unistd.h> #include <signal.h> #include <sys/signal.h> void alarm_handler(int signum){ printf("Buzz Buzz Buzz\n"); } int main(){ //set up alarm handler signal(SIGALRM, alarm_handler); //schedule alarm for 1 second alarm(1); //do not proceed until signal is handled pause(); }
The program looks very much like our other signal handling
programs, except this time the signal is delivered via the
alarm()
call. Additionally, we are introducing a new system call,
pause()
.
The pause()
call will "pause" the program until a signal is
delivered and handled. Pausing is an effective way to avoid busy
waiting, e.g., while(1);
, because the process is suspended during
a pause and awoken following the return of the signal handler.
1.2 Recurring Alarms
Alarm can be set continually, but only one alarm is allowed per
process. Subsequent calls to alarm()
will reset the previous
alarm. Suppose, now, that we want to write a program that will
continually alarm every 1 second, we would need to reset the alarm
once the signal is delivered. The natural place to do that is in
the signal handler:
void alarm_handler(int signum){ printf("Buzz Buzz Buzz\n"); //set a new alarm for 1 second alarm(1); } int main(){ //set up alarm handler signal(SIGALRM, alarm_handler); //schedule the first alarm alarm(1); //pause in a loop while(1){ pause(); } }
After the first SIGALRM
is delivered and "Buzz Buzz Buzz" is
printed, another alarm is schedule via alarm(1)
. The process will
resume after the pause()
, but since it is in a loop, will return
to a suspended state. The result is an alarm clock buzzing every 1
second. Running with time
utility, after about 4 seconds, we saw
4 buzzers.
#> time ./buzz_buzz Buzz Buzz Buzz Buzz Buzz Buzz Buzz Buzz Buzz Buzz Buzz Buzz ^C real 0m4.473s user 0m0.001s sys 0m0.002s
One thing to note about this example is that while the signal
handler code runs asynchronously, it is part of the process
program. Calling alarm()
not in the main method is a perfectly
fine thing to do and necessary.
1.3 Resetting Alarms
Let's suppose we want to add a snooze function to our alarm. If the
user enters Ctrl-c
then we want to reset the alarm to 5 seconds
before buzzing again, like snooze. We can easily add a signal
handler to do that.
void sigint_handler(int signum){ printf("Snoozing!\n"); //schedule next alarm for 5 seconds alarm(5); } void alarm_handler(int signum){ printf("Buzz Buzz Buzz\n"); //set a new alarm for 1 second alarm(1); } int main(){ //set up alarm handler signal(SIGALRM, alarm_handler); //set up signint handler signal(SIGINT, sigint_handler); //schedule the first alarm alarm(1); //pause in a loop while(1){ pause(); } }
And we can see that the output matches our expectation using the
time utility. Note we need to use Ctrl-\
to quit the process.
#>time ./snooze_buzz Buzz Buzz Buzz Buzz Buzz Buzz ^CSnoozing! Buzz Buzz Buzz Buzz Buzz Buzz ^CSnoozing! Buzz Buzz Buzz Buzz Buzz Buzz ^\Quit: 3 real 0m15.469s user 0m0.001s sys 0m0.003s
There is some interesting dilemas here: What happened to the last
alarm? And, what happens if I type Ctrl-C
multiple times, how
long will it snooze? The anser is, only one alarm may be schedule
at one time. Calling alarm()
again will reset any previous
alarms, so the answer to the questions is that (1) the previous
alarm is replaces, and subsequent snoozes only resets the previous
snozoe back to 5 seconds.
If that's the case, how might we unschedule a previously scheduled
alarm. The way to do that is by scheduling an alarm for 0 seconds,
alarm(0)
. For example, we can finish our alarm clock by adding an
"off" switch that listens for Ctrl-\
or SIGQUIT
, which will
unschedule the alarm and reset the signal handler for Ctrl-c
back
to the default.
void sigquit_handler(int signum){ printf("Alarm Off\n"); //turn off all pending alarms alarm(0); //reinstate default handler for SIGINT // Ctrl-C will now terminate program signal(SIGINT, SIG_DFL); } void sigint_handler(int signum){ printf("Snoozing!\n"); //schedule next alarm for 5 seconds alarm(5); } void alarm_handler(int signum){ printf("Buzz Buzz Buzz\n"); //set a new alarm for 1 second alarm(1); } int main(){ //set up alarm handler signal(SIGALRM, alarm_handler); //set up signint handler signal(SIGINT, sigint_handler); //set up signint handler signal(SIGQUIT, sigquit_handler); //schedule the first alarm alarm(1); //pause in a loop while(1){ pause(); } }
And we can track the output:
#>./offswitch_buzz Buzz Buzz Buzz Buzz Buzz Buzz Buzz Buzz Buzz ^CSnoozing! ^\Alarm Off ^C
While this is a simple example, it demonstrates a lot of power in signal handling and how even in asynchronous settings, a lot of power programming concepts can be used. It's a totally different way to communicate with programs.
2 sigaction()
and Reentrant Functions
Now, we're starting to get a bit better with signal handling, we need to turn our attention back to the pesky asynchronous nature of signal handling. In the previous part, we harnessed asynchronicity to program with just the signal handlers, but we now need to consider how signal handlers might affect the primary control flow, in particularly when a system call is executed.
2.1 sigaction()
To start, we need to learn a more advanced form of the signal()
system call, sigaction()
. Like signal()
, sigaction()
allows
the programmer to specify a signal handler for a given signal, but
it also enables the programmer to retrieve additional information
about the signaling process and set additional flags and etc.
The decleration of sigaction()
is as follows:
int sigaction(int signum, const struct sigaction *act, struct sigaction *oldact);
The first argument is the signal to be handled, while the second and
third arguments are references to a struct sigaction
. It is in the
struct sigaction
that we set the handler function and additional
arguments. It has the following members:
struct sigaction { void (*sa_handler)(int); void (*sa_sigaction)(int, siginfo_t *, void *); sigset_t sa_mask; int sa_flags; };
The first two fields, sa_handler
and sa_sigaction
are function
references to signal handlers; sa_handler
has the same type as the
handlers we've been using previously, and we can now write a simple
hello world program with sigaction()
.
void handler(int signum){ printf("Hello World!\n"); } int main(){ //declare a struct sigaction struct sigaction action; //set the handler action.sa_handler = handler; //call sigaction with the action structure sigaction(SIGALRM, &action, NULL); //schedule an alarm alarm(1); //pause pause(); }
We'll look at using the more advanced sa_sigaction
handler later,
but there are other important differences between signal()
and
sigaction()
that are worth exploring. In particular, using
sigaction()
allows us to explores reentrant functions.
2.2 Reentrant Functions
Recall that when a signal handler is invoked, this is done outside the control flow of the program. Normally, the asynchronous invocation of the signal handler is not problematic: the context of the program is saved; the signal handler runs; and, the original context of the program is restored.
However, what happens when the context of the program is within a
blocking function, like reading from a device (read()
) or waiting
for a process to terminate (wait()
). The arrival of the signal
and invocation of the signal handler will interrupt the process,
waking it from a blocking state to execute the signal handler, but
what happens when it returns to the program?
The answer to that question depends on the operation being
performed. Most functions are reentrant and can be restarted in
such cases, but others are explicitly not. For example pause()
is
explicitely not reentrant by design; once intrupted, it should not
return to a blocking state. But functions like read()
and
wait()
need to be told to restart.
2.3 Interrupting System call EINTR
Let's first consider a simple example. Here is a rude little program that will ask for a users name, but if they don't answer within 1 second, it starts barking at the user "What's taking so long?"
void handler(int signum){ printf("What's taking so long?\n"); alarm(1); } int main(){ char name[1024]; struct sigaction action; action.sa_handler = handler; sigaction(SIGALRM, &action, NULL); alarm(1); printf("What is your name?\n"); //scanf returns the number of items scanned if( scanf("%s", name) != 1){ perror("scanf fail"); exit(1); } printf("Hello %s!\n", name); }
Running it, you can see that, yes, if you were to enter your name quickly, the program plays nice:
#> ./scanf_fail What is your name? adam Hello adam!
But, if your late at all, it should start the barking process, but that's actually not what happens:
#> ./scanf_fail What is your name? What's taking so long? scanf fail: Interrupted system call
Instead, we get an error in the scanf()
function, which is a
library function that must call read()
to read from standard
input. The read()
is interupted, which results in the error
message "Interrupted system call" whose error number is
EINTR
. From the man page for read:
EINTR The call was interrupted by a signal before any data was read; see signal(7).
And we can follow up by reading in man 7 signal
:
Interruption of System Calls and Library Functions by Signal Handlers If a signal handler is invoked while a system call or library function call is blocked, then either: * the call is automatically restarted after the signal handler returns; or * the call fails with the error EINTR. Which of these two behaviors occurs depends on the interface and whether or not the signal handler was established using the SA_RESTART flag (see sigaction(2)).
To avoid this scenario we need to set an additional flag for
sigaction()
:
struct sigaction { void (*sa_handler)(int); void (*sa_sigaction)(int, siginfo_t *, void *); sigset_t sa_mask; int sa_flags; //<--- };
What we are going to do, is update our annoying program from before
to use a SA_RESTART
flag so that read()
will be restarted after
the signal handler returns:
2.4 SA_RESTART
If we take another look at the struct sigaction
, there is a field
fo flags:
void handler(int signum){ printf("What's taking so long?\n"); alarm(1); } int main(){ char name[1024]; struct sigaction action; action.sa_handler = handler; action.sa_flags = SA_RESTART; //<-- restart sigaction(SIGALRM, &action, NULL); alarm(1); printf("What is your name?\n"); //scanf returns the number of items scanned if( scanf("%s", name) != 1){ perror("scanf fail"); exit(1); } printf("Hello %s!\n", name); }
2.5 Not all System Calls are Reentrant
It might seem like we've solved all the problems with the
SA_RESTART
flag, but not all system calls are reentrant. You can
see a complete listing in man 7 signal
, but we'll focus on one
you might encounter in your programing. The sleep()
system call
is not reentrant.
We can see this with a simple example:
void handler(int signum){ printf("Alarm\n"); alarm(1); } int main(){ struct sigaction action; action.sa_handler = handler; action.sa_flags = SA_RESTART; //<-- restart sigaction(SIGALRM, &action, NULL); //alarm in 1 second alarm(1); //meanwhile sleep for 2 seconds sleep(2); //how long does the program run for? }
A handler for SIGALRM
is established with the SA_RESTART
flag,
so all should be good. An alarm is scheduled for 1 second and then
the program should sleep for 2 seconds. The question is: How long
does the program take to run?
There are two possibilities. First, it could take 2 seconds because
SIGALRM
is handled the sleep()
is restarted with an remaining 1
second to sleep, totaling 2 seconds worth runtime. Alternatively,
the program will run for 1 second; once SIGALRM
is handled, the
sleep will not be restared, and the program terminates with 1
second of runtime. Let's run it and find out.
#> time ./sleep_restart Alarm real 0m1.005s user 0m0.001s sys 0m0.002s
The program runs for only 1 second, and that is because sleep()
is not reentrant. It cannot be restarted after a signal
handler. This is just a singular example, but there are other
system calls that meet these conditions, some you might also use,
like send()
and recv()
for network socket programming, and
understanding the properties of reentrant system calls is important
to becoming an effective systems programmer.